de robertino24 » 07 Feb 2014, 23:14
Buna seara,
1. Pirita = FeS2, cu masa moleculara M = A(Fe) + 2xA(S) = 56 + 2x32 => M = 120 g/mol
Daca in 120 g pirita ..... avem..... 64 g S
Dar in 100 g pirita ..... avem..... x => x = 6400/120 => x = 53,33% masice S
2. cele 40 kg de pirita reprezinta masa impura (mip)
puritatea unei substante (p%) = (masa pura (mp) x 100)/ mip = 80% (din datele problemei), si deci => mp = (mip x p%)/100 => mp = (40 x 80)/100 => mp = 32 kg pirita pura.
M pirita = 56 + 2x32 => M = 120 kg/kmol
Daca in 120 kg pirita ..... avem..... 56 kg Fe
Dar in 32 kg pirita ....... avem..... x kg Fe => x = 1792/120 => x = 14,933 kg Fe => x = 14933 g Fe
Sper ca informatiile primite sa iti fie de ajutor.
Mult succes in continuare..!